Thie Distance and Midpoint Formulas
The Distance Formula
Points A and B have coordinates (2, 3) and (5, 7). The distance from point A to point B is the length of segment AB. You can find that distance by drawing a right triangle, finding the lengths of its legs, and then using the Pythagorean Theorem:
Notice that the horizontal leg's length can be found by subtracting the x-coordinates of the points and the vertical leg's length can be found by subtracting the y-coordinates of the points. In general, if the points have coordinates (x1, y1) and (x2, y2), then the distance d between them can be found by the Pythagorean Theorem:
or
Example:
Find the length of segment CD if the coordinates of C are (–4, 7) and the coordinates of D are (2, 3).
Solution:
The Midpoint Formula
On the number line, suppose point A has coordinate 17 and point B has coordinate 25. What is the coordinate of the midpoint of segment AB?
You can see from the diagram that the coordinate is 21. A shortcut (if you don't want to draw part of a number line) is to find the average of the coordinates:
In 2 dimensions, the coordinates of the midpoint of two points is the average of their coordinates. For example, if the coordinates of A are (2, 3) and the coordinates of B are (10, 11), then the coordinates of the midpoint M of segment AB are (6, 7).
In general, if the points have coordinates (x1, y1) and (x2, y2), then the midpoint M has coordinates that are the average of these:
An Equation of a Circle
An equation of any shape graphed in the xy-coordinate plane is a statement about all the points on it, using x and y as the coordinates. If you have a circle of radius 5 centered at the origin, the Pythagorean Theorem tells us something that must be true of all points on the circle:
In general, the equation of a circle of radius r centered at the origin is:
The Rhombus Problems
A rhombus is a parallelogram in which all four sides are equal. It is like a "slanted square." Suppose points A, B, C, and D have coordinates (0, 0), (3, 4), (8, 4), and (5, 0), respectively:
1. Show that ABCD is a parallelogram.
Solution:
Sides AD and BC are parallel because they are both horizontal. Sides AB and CD are parallel if they have the same slope:
2. Show that ABCD is a rhombus.
Solution:
We already know it is a parallelogram, so now we must show all sides have the same length. Since sides AD and BC are horizontal, their lengths are easy to find:
Now we use the distance formula to find the lengths of the other sides:
So all 4 sides have the same length.
3. Show that the diagonals of ABCD bisect each other.
Solution:
The easiest way to do this is to show the midpoints of segments AC and BD are the same point:
4. Show that the diagonals of ABCD are perpendicular.
Solution:
Two lines are perpendicular if their slopes are opposite reciprocals, so we find the slopes of segments AC and BD:
Since 1/2 and –2 are opposite reciprocals, the diagonals are perpendicular.
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